请给我告诉数学功式?
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/20 14:02:13
请给我告诉数学功式?
你好歹告诉我你几年级的
再问: ��һ���߶�
再答: 1.�յ���ʽ sin(-a)=-sin(a) cos(-a)=cos(a) sin(��2-a)=cos(a) cos(��2-a)=sin(a) sin(��2+a)=cos(a) cos(��2+a)=-sin(a) sin(��-a)=sin(a) cos(��-a)=-cos(a) sin(��+a)=-sin(a) cos(��+a)=-cos(a) 2.���Ǻ�������Ǻ��� sin(a+b)=sin(a)cos(b)+cos(��)sin(b) cos(a+b)=cos(a)cos(b)-sin(a)sin(b) sin(a-b)=sin(a)cos(b)-cos(a)sin(b) cos(a-b)=cos(a)cos(b)+sin(a)sin(b) tan(a+b)=tan(a)+tan(b)1-tan(a)tan(b) tan(a-b)=tan(a)-tan(b)1+tan(a)tan(b) 3.�Ͳ��ʽ sin(a)+sin(b)=2sin(a+b2)cos(a-b2) sin(a)−sin(b)=2cos(a+b2)sin(a-b2) cos(a)+cos(b)=2cos(a+b2)cos(a-b2) cos(a)-cos(b)=-2sin(a+b2)sin(a-b2) 4.2���ǹ�ʽ sin(2a)=2sin(a)cos(b) cos(2a)=cos2(a)-sin2(a)=2cos2(a)-1=1-2sin2(a) 5.��ǹ�ʽ sin2(a2)=1-cos(a)2 cos2(a2)=1+cos(a)2 tan(a2)=1-cos(a)sin(a)=sina1+cos(a) 6.���ܹ�ʽ sin(a)=2tan(a2)1+tan2(a2) cos(a)=1-tan2(a2)1+tan2(a2) tan(a)=2tan(a2)1-tan2(a2)
再问: ��һ���߶�
再答: 1.�յ���ʽ sin(-a)=-sin(a) cos(-a)=cos(a) sin(��2-a)=cos(a) cos(��2-a)=sin(a) sin(��2+a)=cos(a) cos(��2+a)=-sin(a) sin(��-a)=sin(a) cos(��-a)=-cos(a) sin(��+a)=-sin(a) cos(��+a)=-cos(a) 2.���Ǻ�������Ǻ��� sin(a+b)=sin(a)cos(b)+cos(��)sin(b) cos(a+b)=cos(a)cos(b)-sin(a)sin(b) sin(a-b)=sin(a)cos(b)-cos(a)sin(b) cos(a-b)=cos(a)cos(b)+sin(a)sin(b) tan(a+b)=tan(a)+tan(b)1-tan(a)tan(b) tan(a-b)=tan(a)-tan(b)1+tan(a)tan(b) 3.�Ͳ��ʽ sin(a)+sin(b)=2sin(a+b2)cos(a-b2) sin(a)−sin(b)=2cos(a+b2)sin(a-b2) cos(a)+cos(b)=2cos(a+b2)cos(a-b2) cos(a)-cos(b)=-2sin(a+b2)sin(a-b2) 4.2���ǹ�ʽ sin(2a)=2sin(a)cos(b) cos(2a)=cos2(a)-sin2(a)=2cos2(a)-1=1-2sin2(a) 5.��ǹ�ʽ sin2(a2)=1-cos(a)2 cos2(a2)=1+cos(a)2 tan(a2)=1-cos(a)sin(a)=sina1+cos(a) 6.���ܹ�ʽ sin(a)=2tan(a2)1+tan2(a2) cos(a)=1-tan2(a2)1+tan2(a2) tan(a)=2tan(a2)1-tan2(a2)