[(2b/a^2-b^2)+(a/a^2+ab)]÷3/a-b

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/15 20:24:25

[(2b/a^2-b^2)+(a/a^2+ab)]÷3/a-b
=[(2b/(a+b)(a-b)+a/a(a+b)]×(a-b)/3
=[(2b/(a+b)(a-b)+1/(a+b)]×(a-b)/3
=[(2b/(a+b)+(a-b)/(a+b)]×1/3
=(2b+a-b)/(a+b)×1/3
=(a+b)/(a+b)×1/3
=1/3

因式分解a^+b^+2a^b+2ab^+a^+b^+3ab+a+b 化简 (a²+b²/a²-b²-a-b/a+b)÷2ab/(a-b)(a+b)& (a+b/a-b)²×2a-2b/3a+3b÷ab/a²-b² a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab 3ab+3b²/b(a²+2ab+b²) ×a²-b²/a-b ÷b/ a+b/2ab 2AB/A+B （a-b)(a^2+ab+b) 化简若a/b=2 则a*a-ab+b*b/a*a+b*b等于? [(2b/a^2-b^2)+(a/a^2+ab)]÷3/a-b 已知3a*a+ab-2b*b=0(a不等于0,b不等于0),求a/b-b/a-(a*a+b*b)/ab的值. 先化简,再求值;[(2a-b/a b)-(b/a-b)]÷{(a-2b/a b) [ab/(a-b)2]},其中b/a=