化简 √2/4sin(π/4-x)+√6/4cos(π/4-x)
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1
化简 √2/4sin(π/4-x)+√6/4cos(π/4-x)
化简f(x)=(1+√2*cos(2x-π/4))/sin(π/2-x)
化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
f(x)=2SIN^2(x+π\4)-cos(2x+π\6) 化简 谢
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
已知函数f(x)=2sin(x/4)cos(x/4)-2√3sin²(x/4)+√3,且g(x)=f(x+π/
sin x + cos x = √2 * sin (x + Pi/4)
化简 √2/4sin x+√6/4cos x
已知函数f(x)=2√3sin(x+π/4)cos(x+π/4)-sin(2x+π).求f(x)的最小正周期
三角函数已知P(-4,3) 求(cos((π/2)+x)sin(-π-x))/(cos((11π/2)-x)sin((9