如图 AB=AC AD=AE BD=CE,BD与CE相交于点O.求证∠BOC=∠EAD
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC
如图 AB=AC AD=AE BD=CE,BD与CE相交于点O.求证∠BOC=∠EAD
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O,求证:角CAB=角EAD=角BOC
如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……
如图,AB=AC,AD=AE,BD=CE,BD与CE相较与点o,说明∠cab=∠ead=∠boc
如图,AB=AC,AD=AE,BD=CE,BD与CE相交与O.求证:∠CAB=∠EAD=∠BOD.
如图,已知AB=AC,AD=AE,∠EAD=∠CAB,BD与CD相较于点O,求证说明:BD=CE.
初三放缩与相似性已知:如图,线段BD与CE相交于点A,AD:BD=AE:CE求证:AB:AC=AD:AE
如图 AB=AC AD=AE BD CE相交于点O
已知:如图,AB=AC,AD=AE,BD,CE相交于点O.(1)求证:OD=OE (2)AO平分∠BAC吗?为什么
如图,AB=AC,AD=AE,BD、CE交于O,求证:AO平分∠BAC.
已知,如图AB=AC,AD=AE,BD,CE相交于点O.⑴求证OD=OE ⑵AO平分 角BAC吗