24x^2-50x+24=0 ,
用换元法解方程(x^2+5x)^2+10x^2+50x+24=0
X^3-7X^2+18X-24=0
x^2+14x-24=0
解方程(x²+3x+2)(x²-2x-1)(x²-7x+12)+24=0
x+(x+24)+(x+4)/2=7x
怎样用配方发解?2x²+3=5x ,x²-50x+24²=0,4x²-7x+2=
24x^2-50x+24=0 ,
30X-2X=84 5.8X-X=60 6.6X-5X=8 4X-X=24 1.5X-X=1
X+30%X=52 X-10%x=27 20%x=24=40 2x-50%x=30
(x-22)+(x-24)+(x-27)+(x-20)=x
解方程x(x-1)(x-2)(x-3)(x-4)=24
f(x)={x^2+x(x≤0),-x^2+x(x>0)