1/(x-5)-1/(x-6)=1/(x-8)-1/(x-9)的方程怎么解
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1/(x-5)-1/(x-6)=1/(x-8)-1/(x-9)的方程怎么解
原方程变成-1/(x-5)(x-6)=-1/(x-8)(x-9)即(x-8)(x-9)=(x-5)(x-6)
化成x²-17x+72=x²-11x+30即6x=42,解得x=7
再问: 为什么能直接变成 原方程变成-1/(x-5)(x-6)=-1/(x-8)(x-9)?
再答: 1/(x-5)-1/(x-6)通分得(x-6)/(x-5)(x-6)-(x-5)/(x-5)(x-6) =(x-6-(x-5))/(x-5)(x-6) =-1/(x-5)(x-6)
化成x²-17x+72=x²-11x+30即6x=42,解得x=7
再问: 为什么能直接变成 原方程变成-1/(x-5)(x-6)=-1/(x-8)(x-9)?
再答: 1/(x-5)-1/(x-6)通分得(x-6)/(x-5)(x-6)-(x-5)/(x-5)(x-6) =(x-6-(x-5))/(x-5)(x-6) =-1/(x-5)(x-6)
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