if a and b are both positive intergers and a平方-b平方=7 .what i

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if a and b are both positive intergers and a平方-b平方=7 .what is the value of a

原句翻译为：如果a和b都是正整数,且a²-b²=7,那么a的值是多少?
由题意,可得：
a²-b²=7
即（a+b）（a-b）=7
∴a+b=7,a-b=1
或a+b=-7,a-b=-1
解得：a=4或-4,b=3或-3
又∵a,b＞0
∴a=4,b=3
　　答：a的值为4.

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