函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2

函数f(x)的解析式为f(x)=sin(2x+π/3)-根号3sin²x+sinxcosx+根号3/2 函数f(x)=2cosxsin(x+π/3)-根号3sin²x+sinxcosx 已知函数f（X)=sin²x+2根号3sinxcosx-cos²x 已知函数f(x)=sin^x+根号3sinxcosx+2cos^x,x属于R 已知函数f(x)=sin^2 x+2根号3sinxcosx+sin(x+π/4)sin(x-π/4),x属于R,求f(x 函数f(x)=sin^4x+2根号3sinxcosx-cos^4x的值域为 已知函数f(x)=2sin²x+2根号3sinxcosx+1 已知函数f（x）=2cosx*sin（x+π/3）-根号3sin^x+sinxcosx 1.求函数f（x)的单调递减区间 已知函数f(x)=cos^2x-sin^2x+2根号3sinxcosx+1 已知函数f(x)=根号3(sin^2x-cos^2x)-2sinxcosx 已知函数f(x)=2根号3sinxcosx+2sin^2x-1,x 已知函数f(x)=2cosxsin(x+60°)-根号3sin^2x+sinxcosx