1/4 1/4 1/4 1/4=1/2

1/2,1/4, 1/4 1/4 1/4 1/4=1/2 4 4 4 4=1 4 4 4 4=2 4 4 4 4=3 填标点符号 (（1^4+1/4)(3^4+1/4)(5^4+1/4).(19^4+1/4))/((2^4+1/4)(4^4+1/4) （1^4/4)(3^4+1/4)...(19^4+1\4) \ (2^4+1/4)(2^4+1/4)(4^4+1/4). 4 4 4 4 4=0 4 4 4 4 4=1 4 4 4 4 4=2 4 4 4 4 4=3 4 4 4 4 4=4 (1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/ 求[(1^4+1/4)(3^4+1/4)(5^4+1/4)……(19^4+1/4)]/[(2^4+1/4)(4^4+1/ 1、1/2、1/4、1/7 (1+1/2+1/3+1/4)×(1/2+1+1/3+1/4+1/5)×(1/2+1/3+1/4) =简便方法 1/1×2+1/1-1/2:；1/2×4=1/2×（1/2-1/4）;1/58×=1/3(×1/5-1/8) (1/2-1/4)+(1/4-1/6)+…+(1/48-1/50)=( ) 为什么?