main() {int aa[4][4]={{1,2,3,4},{5,6,7,8},{3,9,10,2},{4,2,9,

#includevoid main(){int aa[4][4]={{1,2,3,4},{5,6,7,8},{3,9,1 main() {int aa[4][4]={{1,2,3,4},{5,6,7,8},{3,9,10,2},{4,2,9, #define N 10 main() { int a[N]={1,2,3,4,5,6,7,8,9,10} int i, main() { int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int *b; b=a; int main() { int a[9] = {1,2,3,4,5,6,7,8,9}; int b[9] = {1,2 下列程序的输出结果是int main(void){int a[10] = {0,1,2,3,4,5,6,7,8,9}, #include main( ) { int a[4][4]={1,2,3,4,5,6,7,8,9,10,11,12,1 (5)main( ) { int k; int a[3][3]={1,2,3,4,5,6,7,8,9}; for(k=0 main(){int x[]={1,2,3,4,5,6,7,8,9}int s,i,*p;s=0;p=&x[0];fpr Main() { Int i,s=0,t[]={1,2,3,4,5,6,7,8,9}; #include main(){int a[]={1,2,3,4,5,6,7,8,9,0},*p; p=a; print main() { int i,*ptr; int array[]={2,4,6,8,10}; ptr=array; fo