Observe that 18 = 42 + 12 + 12 + 02.How many of the first fi
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Observe that 18 = 42 + 12 + 12 + 02.How many of the first fifteen positive integers can be written as the sum of the squares of four integers
马上要考试啦T 后面 的四个数分别是是4的二次方,1的二次方,1的二次方,0的二次方,别看错了.
马上要考试啦T 后面 的四个数分别是是4的二次方,1的二次方,1的二次方,0的二次方,别看错了.
观察18=42+12+12+02.请问前十五正整数,有多少个数字可以写成4个整数的平方之和呢?
1=12+02+02+02
2=12+12+02+02
3=12+12+12+02
4=12+12+12+12或4=22+02+02+02
5=22+12+02+02
..
..
..
13=32+22+02+02
14=32+22+12+02
15=32+22+12+12
由观察可知,4个整数可以重复,还包括0,这样一来,前15个正整数都是可以写成题目所给出的形式的.综上,答案就是15了.
请参考采纳.
1=12+02+02+02
2=12+12+02+02
3=12+12+12+02
4=12+12+12+12或4=22+02+02+02
5=22+12+02+02
..
..
..
13=32+22+02+02
14=32+22+12+02
15=32+22+12+12
由观察可知,4个整数可以重复,还包括0,这样一来,前15个正整数都是可以写成题目所给出的形式的.综上,答案就是15了.
请参考采纳.
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