2lg5/lg2*2lg2/lg3*2lg3/lg5=多少,

(lg3(lg2+lg5)/lg2lg5) *[ lg5(lg3+lg9)/lg3lg9]*lg2=(lg3+2lg3) 2lg5/lg2*2lg2/lg3*2lg3/lg5=多少, （2lg5·2lg2·2lg3）/（lg5·lg2·lg3）= lg2/lg3+lg5/lg3 lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5 (2lg5/lg2)*(2lg2/lg3)*(2lg3/lg5)求解,谢谢! 请问lg2.lg3.lg5=? lg2*lg3=?lg5/lg2=? (lg5)^2+lg5.lg2= (lg2)^2+lg2*lg5+(lg5)^2= lg2、lg3、lg5分别约等于多少 lg5×lg2×lg3等于多少?为什么