(2xsin(y/x)-ycos(y/x))dx+(xcos(y/x)+1)dy=0 求y
(2xsin(y/x)-ycos(y/x))dx+(xcos(y/x)+1)dy=0 求y
求证 cos*xcos*y + sin*xsin*y + sin*xcos*y + xin*ycos*x = 1
求解微分方程:[x-ycos(y/x)]dx+xcos(y/x)dy=0.
求解微分方程 (x-ycos(y/x))dx+xcos(y/x)dx=0
ycos(y/x)=((x^2/y)*sin(y/x)+xcos(y/x))dy/dx 请问这道题该用什么方法解 如果代
求方程[xcos(x+y)+sin(x+y)]dx+xcos(x+y)dy=0的通解,
(x+y)dy+(x-y)dx=0求通解
求dy/dx=(x-y+5)/(x+y-2)
求下列式子dy/dx (1) x^2y-x+y=0;(2) x√y =y-1
高数导数求由方程ycos=sin(x-y) 确定的隐函数 y=y(x) 的导数dx/dy
y=xe^y,求dy/dx |x=0
cos(x+y)+y=1 求dy/dx