当x^2+x=3=0,求x^5+3x^4+2x^3+2x^2-10x+5
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当x^2+x=3=0,求x^5+3x^4+2x^3+2x^2-10x+5
x^2+x+3=0
x^2+x=-3
x^5+3x^4+2x^3+2x^2-10x+5
=x^5+x^4+2x^4+2x^3+2x^2-10x+5
=x^3(x^2+x)+2x^4+2x^3+2x^2-10x+5
=-3x^3+2x^4+2x^3+2x^2-10x+5
=2x^4-x^3+2x^2-10x+5
=2x^4+2x^3-3x^3+2x^2-10x+5
=2x^2(x^2+x)-3x^3+2x^2-10x+5
=-6x^2-3x^3+2x^2-10x+5
=-3x^3-4x^2-10x+5
=-3x^3-3x^2-x^2-10x+5
=-3x(x^2+x)-x^2-10x+5
=9x-x^2-10x+5
=-x^2-x+5
=-(x^2+x)+5
=3+5
=8
x^2+x=-3
x^5+3x^4+2x^3+2x^2-10x+5
=x^5+x^4+2x^4+2x^3+2x^2-10x+5
=x^3(x^2+x)+2x^4+2x^3+2x^2-10x+5
=-3x^3+2x^4+2x^3+2x^2-10x+5
=2x^4-x^3+2x^2-10x+5
=2x^4+2x^3-3x^3+2x^2-10x+5
=2x^2(x^2+x)-3x^3+2x^2-10x+5
=-6x^2-3x^3+2x^2-10x+5
=-3x^3-4x^2-10x+5
=-3x^3-3x^2-x^2-10x+5
=-3x(x^2+x)-x^2-10x+5
=9x-x^2-10x+5
=-x^2-x+5
=-(x^2+x)+5
=3+5
=8
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