d(sin(2t))====?
为什么sin'wt=(wt)'*sin't
matlab中假设t=0:0.1:2*pi;为什么y=t.*sin(t).*sin(t)不等于y=t.*(sin(t))
在matlab中sin(t).和sin(t)有什么区别 例如:t=0:pi/20:2*pi y1=sin(t).*sin
用matlab 如何作出y与t的图?y=(sin(t)-sin(t0))^2 且 cos t+t*sin t-cos t
已知函数f(t)=-sin^2t+sint+a
dx/dt=6t+2,dy/dt=(3t+1)sin(t^2),求d^2y/dx^2
MATLAB题用Simulinkf仿真两个正弦信号相减y=sin(t)-sin(2*t).
t=0:pi/100:10*pi; x=2*(cos(t)+t*sin(t)); y=2*(sin(t)-t*cos(t
cos^3+sin^3 求化简设t=cos+sin
英语翻译t = 0:.001:.25;x = sin(2*pi*50*t) + sin(2*pi*120*t);y =
x=2sin(t),y=cos(t+pie),求dy/dx,和d^2y/dx^2,在点(0,-1)
x_t=sin(2*pi*f1*t)+sin(2*pi*f2*t)+sin(2*pi*f3*t);n_t=wgn(1,M