AB=CD,AF=CE,BE⊥AC,DF⊥AC,求证BE=DF

  已知：如图,BE⊥AC,DF⊥AC,垂足分别是点E、F.AF=CE,BE=DF.求证：AB=CD 如图所示:BA⊥AC,DC⊥AC,AF=CE,BE=DF.求证;△ABE全等于△CDF,BE∥DF 如图所示,已知CE垂直AB于E,DF垂直AB于F,AF=BE,AC=BD.求证：CE＝DF 如图,已知CE⊥AB,DF⊥AB,AC=BD,AF=BE,则CE=DF.请说明理由. 如图,AB、CD相交于点O,AC//DB,AF=BE,OC=OD,AC=DB.求证：DF=EC且DF//EC 如图,已知AD=BC,BE⊥AC于E,DF⊥AC于F,且BE=DF.求证AB‖CD 在四边形ABCD中,AB‖CD,AB⊥CD,∠AEB=∠CED.F为BC的中点,求证AF=DF=0.5（BE+CE) 如图,已知AB⊥BC,AE⊥EF,AC=DF,BE=CF.求证AC平行于DF. 如图 等边△ABC中,D为AC中点,CE为BC的延长线,且CE=CD,取BE中点F,求证：DF⊥BE. 如图,等边△ABC中,D为AC中点,CE为BC的延长线,且CE=CD,取BE中点F,求证：DF⊥BE. 如图所示,已知CE垂直AB于E,DF垂直AB于F,AF=BE,AC=BD.求证：AB∥BD 如图,E,F是线段AC上两点,AF=CE,DF=BE,DF平行BE.求证：△AFD全等于△CEB