英语数学题:The integer solutions of the inequalities about"x" [3(
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英语数学题:
The integer solutions of the inequalities about"x" [3(x-a)+2≥2(1-2x-a)] and [(x+b)÷3<(b-x)÷2] are 1,2,3,then the number of integer pairs (a,b) is ( )
先翻译
The integer solutions of the inequalities about"x" [3(x-a)+2≥2(1-2x-a)] and [(x+b)÷3<(b-x)÷2] are 1,2,3,then the number of integer pairs (a,b) is ( )
先翻译
大家都写错了,我的才对,
翻译:所给的关于x的不等式的整数解是1,2,3.,那么由整数a跟b组成的组合有几个?
由[3(x-a)+2≥2(1-2x-a)] 得x≥ a/7
由[(x+b)÷3<(b-x)÷2] 得x<b/5
所以a/7≤x<b/5
因为x的不等式的整数解是1,2,3
所以1≥a/7>0,解得7≥a>0,a可以取7,6,5,4,3,2,1,共7种可能
3
翻译:所给的关于x的不等式的整数解是1,2,3.,那么由整数a跟b组成的组合有几个?
由[3(x-a)+2≥2(1-2x-a)] 得x≥ a/7
由[(x+b)÷3<(b-x)÷2] 得x<b/5
所以a/7≤x<b/5
因为x的不等式的整数解是1,2,3
所以1≥a/7>0,解得7≥a>0,a可以取7,6,5,4,3,2,1,共7种可能
3
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