多元函数的极限 [lim xln(1+xy)]/(x+y) x→0,y→0 极限是否存在?
多元函数极限求解lim(x→∞,y→∞)((x+y)/(x^2+xy+y^2))=?
怎么求多元函数极限lim sin(xy)(x,y)->(0,0) ------- 怎么求这个极限啊?x
多元函数极限lim sin(xy)/x (x.y) -> (0.2) = lim {[sin(xy) / xy ] *
求两道多元函数的极限lim=(x²-y²-2x+2y)/(x+ y-2) ① (x,y)→(2,0)
求下列各极限 lim(x,y)→(0,1) (2-xy)/(x^2+2y)
求极限lim(x,y)→(0,0) [1-cos(xy)]/xy^2.
二元函数求极限问题lim[﹙2-e^xy﹚^1/2]-1=lim1/2(1-e^xy)(x,y)→(0,0) (x,y)
跪求极限Y=lim (xy+1)/x^4+y^4,当(x,y)→(0,0),
用洛必达法则求极限:lim(x→0)xln(e^x-1)
数学极限计算lim(x,y)→(0,0) xy/ [√(2-e^xy)-1]= lim(x,y)→(0,0) -xy/(
求二重极限lim[xy/(1+x^2+y^2)],x→0,y→0.求详细步骤
lim(x→0y→1)(1+xe^y)^(2y+x/x)求极限