如图是函数f(x)=2sin(ωx+φ)(ω>0,-π/2

已知函数f(x)=(√3sinωx+cosωx)*sin(-3π/2+ωx)（0 已知函数f(x)=sin(ωx+φ)(ω>0,-π/2 已知函数f(x)=2sin(ωx+φ-π/6)(0 函数f(x)=sin(ωx+ф)+cos(ωx+ф)(ω>0,-π/2 函数f(x)=根号3sinωx+cosωx(ω＞0）怎样变为f(x)=2sin(ωx+π/6） 已知函数f(x)=sin(ωx+φ)(0 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 已知函数f(x)=sin(2x+φ) (0 函数f(x)=sin(2x+φ)(0 设函数f(x)=sin(2x+φ)(0