解释这个计算题x+a%3*(int)(x+y)%2/4设x=2.5,a=7,y=4.7.这个题目最后的结果为什么是2.5

x+a%3*(int)(x+y)%2/4 设x=2.5 a=7 y=4.7 设X=2.5,a=7,y=4.7,表达式x+a%3*(int)(x+y)%2/4的值是? int a=7;float x=2.5,y=4.7 x+a%3*(int)(x+y)%2\4的值为什么等于2.5 设x=2.5 a=7 c=4.7,算术表达式x+a%3*（int）（x+y）%2/4的值是? 求算术表达式x+a%3*(int)(x+y)%2/4的值,设x=2.5,a=7,y=4.7中a%3*(int)(x+y) C语言中的算数表达式设x=2.5,a=7,y=4.7 则x+a%3*(int)(x+y)%2/4的值为多少? 若有定义：int a=7;float x=2.5,y=4.7; ,则表达式x+a%3*(int)(x+y)%2/4的值是 若有定义“int a=7;float x=2.5,y=4.7;”,则表达式x+a%3*(int)(x+y)%2/4的值是 若有定义:int a=7;float x=2.5,y=4.7;则表达式x+a%3*(int)(x+y)%2/4的值是? 已知：a=7,x=2.5,y=4.7(a整型,x,y浮点),计算算术表达式x+a%3*(int)(x+y)%2/4的值. 15.若有定义:int a=7;float x=2.5,y=4.7;则表达式x+a%3*(int)(x+y)%2/4的值 c语言中x+a%3*(int)(x+y)%2/4 x=2.5 a=7 y=4.7