已知AD=AB,AC=AE,∠DAB=∠CAE
已知三角形ABC 分别以AB、AC为边向外作三角形ABD和三角形ACE,且AD=AB,AC=AE,∠DAB=∠CAE.
已知,如图所示,AB=AC,AD=AE,∠DAB=∠CAE,CD与BE相交于P、求证 PA平分∠DPE
已知△ABC,分别以AB、AC为边作△ABD和△ACE,且AD=AB,AC=AE,∠DAB=∠CAE,连接DC与BE,G
1、已知△ABC,分别以AB、AC为边作△ABD和△ACE,且AD=AB,AC=AE,∠DAB=∠CAE,连接DC与BE
已知三角形ABC,分别以AB,AC为边作三角形ABD和三角形ACE,AD=AB,AC=AE,角DAB=角CAE,
如图,角DAB=角CAE,AB:AD=AC:AE,试说明三角形ABC全等于三角形ADE
已知:如图,AB=AD,AC=AE,∠BAD=∠CAE,求证:BC=DE
已知:如图,AB=AD,AC=AE,∠CAE=∠BAD.求证△EAD≌△CAB
已知:如图,AB/AD=BC/DE=AC/AE,求证:∠BAD=∠CAE
如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE
AB=AD,AC=AE,BC=DE.求证∠BAD=∠CAE
如图,AB/AD=BC/DE=AC/AE,求证:∠BAD=∠CAE