cos(-23π/4)+sin(37π/6)
cos sin π √
已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为
化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)=
sin(π+π/6)-cos(π+π/4)cos(-π/2)+1
sin(-4π/3)cos(-23π/6)tan(25π/4)=?
怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3
1.化简sin²α+cosαcos(π/3+α)-sin²(π/6-α)
函数规律sin^2 π/6+cos^2 π/3+sin π/6 cosπ/3=3/4sin^2 π/9+cos^2 5π
已知 sinα+2cos(5π/2+α)/cos(π-α)-sin(π/2-α)=-1/4 求(sinα+cosα)平方
已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4)
已知α∈(0,π/2),且2sinα-sinαcosα-3cosα=0.求[sin(α+π/4)]/[sin2α+cos
已知3π/4最好把tan化成sin/cos,cot化成cos/sin算,因为我是这样的,然后算得sin@cos@=-3/