a1=9,3a(n+1)+an=4.Sn为an前n项和,求|Sn-n-6|

已知数列 an前n项和为Sn,a1=1,Sn=2a(n+1),求Sn 数列{an}的前n项和为Sn,已知A1=a,An+1=Sn+3^n（三的n次方）,n∈N* 等比数列an的前n项和为sn,sn=1+3an,求：an 数列an的前n项和为Sn,a1=1,a(n+1)=3Sn,a6=? 设数列{an}的前n项和为Sn,a1=10,a(n+1)=9Sn+10 设数列{an}的前n项和为Sn．已知a1=a，an+1=Sn+3n，n∈N*．由 已知数列{an}a1=2前n项和为Sn 且满足Sn Sn-1=3an 求数列{an}的通项公式an 设数列{an}的前n项和为Sn,已知a1=a,an+1=Sn+3^n,n∈N+.设bn=Sn+3n,求数列{bn}的通项 设数列{an}的前n项和为sn,已知a1=a,an+1=sn+3^n,n∈N* (1)设bn=sn-3^n,求数列{bn 数列an的前n项和为Sn,a1=1且3a（n+1)+2Sn=3求an的通向公式 数列an的前n项和为Sn,a1=t,2a(n+1)=-3Sn+4 求a2,a3 t为何值an等比 一道数学题：设数列{an}的前n项和为Sn.已知a1=a,a(n+1)=Sn+3^n,n属于N*.