已知x+y=√2 sin(θ+π/4),x—y=√2 sin(θ—π/4),求证:x²+y²=1.
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/10 15:03:07
已知x+y=√2 sin(θ+π/4),x—y=√2 sin(θ—π/4),求证:x²+y²=1.
显然sin(θ+π/4)=sinθ*sinπ/4 +cosθ*cosπ/4,
sin(θ-π/4)=sinθ*cosπ/4 -cosθ*sinπ/4,
而sinπ/4=cosπ/4= √2/2,
故x+y=√2 sin(θ+π/4)=sinθ+cosθ,
x-y=√2 sin(θ-π/4)=sinθ -cosθ,
两式相加,得到x= sinθ,
两式相减,得到y=cosθ,
显然sin²θ+cos²θ=1,
故x²+y²=1
sin(θ-π/4)=sinθ*cosπ/4 -cosθ*sinπ/4,
而sinπ/4=cosπ/4= √2/2,
故x+y=√2 sin(θ+π/4)=sinθ+cosθ,
x-y=√2 sin(θ-π/4)=sinθ -cosθ,
两式相加,得到x= sinθ,
两式相减,得到y=cosθ,
显然sin²θ+cos²θ=1,
故x²+y²=1
已知sin(x+y)=1,求证:tan(2x+3y)=tany
求证cosx-cosy=-2sin (x+y/2)*sin (x-y/2)
证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+
已知函数y=2sin(2x-π/4)-2根号2sin^2x
已知(x/a)cosθ+(y/b)sinθ=1,(x/a)sinθ-(y/b)cosθ=1,求证(x^2/a^2)+(y
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
已知:3sinY=sin(2X+Y),求证tan(X+Y)=2tanX
已知5siny=sin(2x+y),求证:tan(x+y)=3/2tanx
已知sin(x+y)=1,求证:tan(2x+y)+tany=0
已知sin(x+y)=1,求证:tan(2x+y)+tany=0
求证:sin(x-y)sin(x+y)/sin²xcos²y=1-cot²xtan
求证:sin(x-y)/(sinx-siny)=cos[(x-y)/2]/cos[(x+y)/2]