化简1/(X(X-1))+1/((X-1)(X-2))+1/((X-2)(X-3))+……+1/((X-2009)(X-
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/09/30 23:40:57
化简1/(X(X-1))+1/((X-1)(X-2))+1/((X-2)(X-3))+……+1/((X-2009)(X-2010))
过程
过程
1/(X(X-1))=1/x-1/(x-1)
1/((X-1)(X-2))=1/(x-1)-1/(x-2)
……
1/((X-2009)(X-2010))=1/(x-2009)-1/(x-2010)
所以1/(X(X-1))+1/((X-1)(X-2))+1/((X-2)(X-3))+……+1/((X-2009)(X-2010))=
[1/x-1/(x-1)]+[1/(x-1)-1/(x-2)]+……+[1/(x-2009)-1/(x-2010)]=
1/x-1/(x-2010)
1/((X-1)(X-2))=1/(x-1)-1/(x-2)
……
1/((X-2009)(X-2010))=1/(x-2009)-1/(x-2010)
所以1/(X(X-1))+1/((X-1)(X-2))+1/((X-2)(X-3))+……+1/((X-2009)(X-2010))=
[1/x-1/(x-1)]+[1/(x-1)-1/(x-2)]+……+[1/(x-2009)-1/(x-2010)]=
1/x-1/(x-2010)
化简 x(x-1)+2x(x+1)-3x(2x-5)
化简:1+x+x(1+x)+x(1+x)^2+……+x(1+x)^2006
[x(x+1)+x平方(x-1)]+(-3x)
(x/x-1)+(5x-2)/x*x-x=1 求x(有图)
(x-1)^3(x+1)(x-2)/(x+4)
(x+1)(x+2)(x+3)(x+4)+1
计算 x(x+3)-(x-1)(x-2)
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)
(x+2/x+1)-(x+4/x+3)-(x+3/x+2)+(x+5/x+4)
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2)