1/5+4/(1*5)=1,1/6+4/(2*6)=1/2,1/7+4/(3*7)=1/3,1/8+4/(4*8)=1/

1 2 3 4 5 6 7 8=1 1*1=1 1*2=2 1*3=3 1*4=4 1*5=5 1*6=6 1*7=7 1*8=8 1*9=9 for循环怎 1+2+3+4+5+6+7+8= 1+2+3+4+5+6+7+8+9=? 数列计算 1/2+1/3+1/4+1/5+1/6+1/7+1/8+1/9=? 1/9{1/7[1/5（【x+2】/3+4)+6]+8}=1 1\9{1\7[1\5(x+2\3+4)+6]+8}=1 9/1{7/1[5/1(3/x+4+2)+6]+8}=1 a[2][4]={1,2,3,4,5,6,7,8};b[4][3]={1,2,3,4,5,6,7,8,9,10,11,1 1+1=?1+2+3+4+5+6+7+8+9+.+1000000000000=? 3/1｛7/1[5/1(x+2/3+4)+6]+8｝=3 3 4 9 7 0 1 5 6 8 1 3 1 4 2 5 7=-8