1 2 3 4 5 6 7 8=1

1 2 3 4 5 6 7 8=1 1+2+3+4+5+6+7+8= 1+2+3+4+5+6+7+8+9=? 1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9=? 1+2+3+4+5+6+7+8+9-9-8-7-6-5-4-3-2+1=? (9+8+7+6+5+4+3+2+1)-(1+2+3+4+5+6+7+8+9)×58=? matlab >> [22+3:6,1:8] ans = 1 2 3 4 5 6 7 8 1/9+1/5+3/5+4/9+2/3+7/8+1/6+5/7+3/7+5/8+3/5+1/8+2/9=? 3 4 9 7 0 1 5 6 8 1 3 1 4 2 5 7=-8 a[2][4]={1,2,3,4,5,6,7,8};b[4][3]={1,2,3,4,5,6,7,8,9,10,11,1 10/1*2*3*4+18/3*4*5*6+26/5*6*7*8= 3/1｛7/1[5/1(x+2/3+4)+6]+8｝=3