(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2 ）=?不好意思啊,发错题了.是除

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/06 07:53:52

(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2 ）=?不好意思啊,发错题了.是除以(-1/2x^3y^2）

(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2)
=-(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)*(2x^3y^2)
=1/2xy+1/xy^2+1/3
=(3y+6+2xy^2)/(6xy^2)
1/4等都是系数
则
(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(-1/2x^3y^2)
=-1/2*xy+xy^3+1/3

{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1 （x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3) 已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-( 化简求值：【(x+Y)(X-Y)-(X-Y)的平方+2Y（2-Y）】除4Y,其中X=1 Y=2 3x+2y/4=2x+y/5=x-y+1/6 先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y [(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y,其中x=1/2,y=1/3 先化简,再求值：[(x+y)(x-y)-(x-y)^2+2y(x-3y)]/(-4y),其中x=1,y=-2 3x-2y=1 4x-5y 9y=3x-(x-1),4(x+y)-(2x+4)=8y 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7