∫sin(2x-π/6)cos(3x+π/6)dx

几道不定积分的题∫dx/(x^2-x-6) ∫dx/(4-x^2) ∫sin^2(3x)dx ∫sin^2(x)cos^ ∫sin(x) cos^2(x)dx 定积分上限π/2下限0sin^6x/(sin^6x+cos^6x)dx 定积分∫(-π/2,π/2)(cos^4x+sin^3x)dx= 求解 ∫sin(6x)^3*cos(6x)^8 dx=? 范围[pi/2,0] 微积分求解：∫sin^3 (x) cos^2 (x) dx 求积分：∫sin^2 (x) /cos^3 (x) dx ∫ [cos^3(x)]/[sin^2 (x)]dx ∫sin^3(x)cos^2(x)dx= ∫(cos^3x/sin^2x)dx 证明∫( 0,π／2 ) (f sin x/(f sin x+f cos x) dx=π /4 ∫e^sin x/(e^sin x+e^cos x)dx在0~π／2上的积分