求证:(x2-xy+y2)3+(x2+xy+y2)3能被2x2+2y2整除

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/09/23 08:16:32

(x²-xy+y²)³+(x²+xy+y²)³
立方和
=[(x²-xy+y²)+(x²+xy+y²)][(x²-xy+y²)²-(x²-xy+y²)(x²+xy+y²)+(x²+xy+y²)²]
=(2x²+2y²)[(x²-xy+y²)²-(x²-xy+y²)(x²+xy+y²)+(x²+xy+y²)²]
所以能被2x²+2y²整除

2x2-xy+3y2因式分解 x2 y2+3xy+2 因式分解已知2x=3y,求xy／(x2+y2)-y2／(x2-y2)的值 X2+3xy+y2因式分解 (2x2-3xy+4y2)+(x2+2xy-3y2）化简（要有过程）已知X2次方+XY=3,XY+Y2次方=-2,求下例值:X2次方-Y2次方解方程组x2+y2=20,2x2-3xy-2y2=o 已知:x=3,y=-5,x2-2xy+y2/x2-y2的值是已知x2-xy=-3，2xy-y2=-8，求2x2+4xy-3y2的值．已知x2+xy=3，xy+y2=-2，则2x2-xy-3y2的值为（　　）已知x2+xy=3，xy+y2=-2，则2x2-xy-3y2=______．已知X2次方+XY=3,XY+Y2次方=-2,求下例值:2X2次方-XY-3Y2次方