设数列{an}的前n项和为Sn,且满足Sn-Sn-1+2SnSn-1=0(n≥2)

已知数列{an}的前n项和为Sn，且满足a1=1，Sn-Sn-1=2SnSn-1（n≥2）． 已知数列an的前n项和为sn且满足a1=1,sn-sn-1=2snsn-1拜托各位大神 已知数列an的前n项和为Sn,且满足an+SnSn-1=0(n>=2,n∈N*),a1=1/2. 已知数列{an}的前n项和为Sn，且满足a1＝12，an+2SnSn-1=0（n≥2）． 已知数列{an}的前n项和为Sn,且满足a1=1/2,an+2SnSn-1=0(n>=2) 已知数列{an}的前n项和为Sn,且满足an+2SnSn-1=0(n≥2),a1=1/2(1)判断{1/Sn},、{An 已知数列{an}的前n项和为Sn,且满足an+2Sn+Sn-1=0(n≥2),a1+1/2 数列an的前n项和sn满足an+2snsn-1=0(n>=2)且a1=1/2 1、求证数列1/sn为等差数列 2、求通项 已知数列{an}的前n项和为Sn,且满足an+2Sn*Sn-1=0,a1=1/2.求证：{1/Sn}是等差数列 已知数列{an}的前n项和为Sn．且满足a1＝12，an＝−2SnSn−1(n≥2) 已知数列an的前n项和为Sn,且满足a1=1/2,An=-2SnSn-1 n>=2 已知数列{an}的前n项和为Sn,且满足a1=1/2,an=-SnSn-1（n>=2）