若数列{an} 满足：a

若数列{an}满足a 数列{an}满足a 若数列{an}满足1a 已知数列{an}满足a 若数列{An}满足A1=1,A(n+1)=An/(2An + 1) 【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列｛1/an｝为等差数列,并求出数列{an 已知f(x)={(3-a)*x-3(x7)},数列{an}满足an=f(n),n∈N*,若数列{an}是递增数列,则(a 若数列an满足a1=2,a(n+1)=3an+2,求数列的通项公式 数列an中,a1=1,a2=2数列bn满足an+1+（-1）n次an,a属于N* （1）若an等差数列... 若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点（an,an+ 已知数列{an}满足a1=1,a(n+1)=2an+1(n∈N)(1)求数列{an}的通项公式（2）若数列{bn}满足4 已知数列{an},如果数列{bn}满足b1=a1,bn=an+a(n-1)则称数列{bn}是数列{an}的生成数列