lim(an^2/(3n+1)-n)=b a+b=?

lim (n→∞) (n^2/(an+b)-n^3/(2n^2-1))=1/4 求a,b 已知lim[(an^2+5n-2)/(3n+1)-n]=b,求a,b的值 lim（n2+2n+2）/（n+1）-an）=b,求a,b 已知：lim (n→∞) [(n^2+n)/(n+1)-an-b]=1 ,求a,b的值 a,b为常数.lim（n->无穷）an^2+bn+2/2n-1=3 求a,b 若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b lim[(n^2+1)/(n+1)-an-b]=o求a和b的值 lim[1/(a-1)^n]=0 求a的范围 lim(n到无穷) n2/n+1+an+b=0.a=?b=? 若极限lim((3n^2+4)/(n+2)-an+b)=6,则a=_,b=_ lim(n趋于无穷大)(5n^2+3n)/(an^2+b)=多少 若lim[(an^2+bn+c)/(2n-3)]=-2,则a+b=