2x+y+3z=10,3x+4y+2z=15,则x+y+z=

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知,方程组:4x-3y-7z=0 x+2y=10z 则(x-y+z)÷(x+y+z)=—— x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, x/2=y/3=z/5 x+3y-z/x-3y+z 若{x+3y+10z=0 则 (x+y-z)/(x-y+z) (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai x+2y+3z=10,x-y+4z=10,x+3y+2z=2 已知,x/2=y/3=z/4,则(2x+y-z)/(3x-2y+z)=? x-y+4z=10,x+3y+2z=2,x+2y+3z=11. x+y+z=4 2x+3y-z=6 3x+2y+2z=10 x-3y+z=0,3x-2y-4z=0,则x:y:z=多少? {2x+3y-4z=-5 x+y+z=6 x-y+3z=10