神马作文网a 4kg body is placed on horizontal ground.The coefficient of
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a 4kg body is placed on horizontal ground.The coefficient of dynamic friction between the body and the ground is 0,2.The object is acted upon by a force of 30 N that encloses an angle of 20 with horizontal.Find the friction force and the acceleration of the body
frictional force
0.2*(4*9.8-30*Sin20)
= 5.8 N
acceleration
(30*Cos20-0.2*(4*9.8-30*Sin20))/4
= 5.6 m/s^2
0.2*(4*9.8-30*Sin20)
= 5.8 N
acceleration
(30*Cos20-0.2*(4*9.8-30*Sin20))/4
= 5.6 m/s^2
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