一道英文物理题A 4kg body is placed on horizontal ground.The coeffic

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一道英文物理题
A 4kg body is placed on horizontal ground.The coefficient of dynamic friction between the body and the ground is 0,2.The object is acted upon by a force of 30 N that encloses an angles of 20 whith horizontal.Find the friction force and the acceleration of the body.

翻译:一个4kg的物体放置在水平面上.物体和地面之间的摩擦因数是0.2.物体受一个与水平面夹角是20度的力的作用,力大小是30N.求摩擦力和物体的加速度.
竖直方向上物体没有加速度,受力平衡:
Fsin20度+N=mg 其中,F是拉力,N是支持力,令g=9.8m/s^2
f=μN f是摩擦力,解出:f=μ(mg-Fsin20度)=5.83N
水平方向上有加速度a.则根据牛顿第二定律:Fcos20度-f=ma
解出:a=5.59m/s^2
In the vertical direction,the body doesn't have acceleration:
Fsin20+N=mg,
F is the force that act upon the body,N is the force of support from the ground.Let g be g=9.8m/s^2
f=μN,
f is the friction force,μ is the coefficient of dynamic friction between the body and the ground.
So,f=5.83N
In the horizontal direction,according to Newton's Second Law:(Fcos20-f)=ma
a is the acceleration.
So,a=5.59m/s^2

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