f(x)=sin (2x-π/4)可以写成f(x)=cos(2x+π/4)
已知f(x)=cos^2x/1+sin^2x求f'(π/4)
证明∫( 0,π/2 ) (f sin x/(f sin x+f cos x) dx=π /4
已知f(x)=cos^2x+sinxcosx g(x)=2sin(x+π/4)sin(x-π/4)
已知函数f(x)=2sin(x/4)cos(x/4)-2√3sin²(x/4)+√3,且g(x)=f(x+π/
已知f(x)=sinx+2sin(π/4+x/2)cos(π/4+x/2).
化简f(x)=(1+√2*cos(2x-π/4))/sin(π/2-x)
f(x)=2SIN^2(x+π\4)-cos(2x+π\6) 化简 谢
已知函数f(x)=2sin(x+π/4)cos(x-π/4)
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+/4π) 三角函数
已知函数f(x)=sin²(π/4+x)+cos²x+1/2求最值
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1