求可逆反应的平衡浓度please cheak over and tell me where I did mistake~

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求可逆反应的平衡浓度
please cheak over and tell me where I did mistake~thanks!

Fe3+ +SCN- =Fe(SCN) 2+
Before the reaction:
[Fe3+]=0.180/0.810=0.222mol/L
[SCN-]=3.70*10^-2 mol/L
Assume that after the reaction [Fe(SCN)2+]= x mol/L
then
K=1.10*10^3=[Fe(SCN)2+]/[Fe3+]/[SCN-]=x/(0.222-x)/(3.70*10^-2-x)
thus
x=3.682*10^-2 mol/L
so after the reaction:[Fe3+]=0.222-3.682*10^-2=1.854*10^-1 mol/L
[SCN-]=3.70*10^-2-3.682*10^-2=1.8*10^-4 mol/L
前面第三题
因为AgSCN是沉淀
所以导致SCN-浓度降低,所以平衡左移
居然把INSOLUBLE的IN忽略掉了- -

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