2x²+y²+2xy-2y+2=0 求x+y=( )
|x+2y+3|+(2x+y)²=0求x²-xy+y²
代数分式 一道题若x÷y=2,则分式(x²-xy+3y²)÷(x²+xy+6y²
已知x/y=3,求x²+2xy-3y²/x²-2xy+y²
x/y=2,求分式x²-xy+3y²/x²+xy+6y²
已知x/y=3,求x²+2xy-3y²/x²-xy+y²的值
已知X²-5XY+6Y²=0,求(X²+3XY)\2Y²的值
已知3x²+xy-2y²=0(x≠0,y≠0),求x/y-y/x-x²+y²/x
2x²+y²+2xy-2y+2=0 求x+y=( )
已知x²-xy-y²=0,且x≠0,y≠0.求代数式(x²-2xy-5y²)/(
已知,x²-2y²-2xy-4y+4=0 求x²+y²的值
已知(x+2)²+|x+y+5|=0,求3x²y+{-2x²y-[-2xy+(x²
已知x+y=1,求1/2x²;+xy+1/2y²;的值