1+2+3+4+5……+9999+10000=?i
计算(1-2i)-(2-3i)+(3-4i)-(4-5i)=
i+2i^2+3i^3+4i^4+…+2010i^2010=?要有步骤``
计算:(1-2i)-(2-3i)+(3-4i)-(4-5i)+…+(1 999-2 000i)-(2 000-2 001
1+i-2i^2+3i^3-4i^4+5i^5
计算(1+2i)+(2-3i)+(3+4i)+(4-5i)+...+(2008-2009i)
1+2+3+4+5……+9999+10000=?i
复数5+3i/4-i=1+i
(1+7i)^2=?(3+2i)*(3-2i)*(-4+i)=?根号3i分之1=?8+3i分之5-2i=?1-2i分之1
已知复数z满足z=1+i+i^2+i^3+…+i^2015,则复数z=?
复数除法 计算1+i/1-i,1/i,7+i/3+4i (-1+i)(2+i)/-i
i+2i^2+3i^3+……+2000i^2000=多少
复数1+i+2i^2+3i^3+……+100i^100