化简[cot(θ+4π)cos(θ+π)sin²(θ+3π)]/[tan(π+θ)cos²(-π-θ

化简[cot(θ+4π)cos(θ+π)sin²(θ+3π)]/[tan(π+θ)cos²(-π-θ 化简：根号（1-tanθ)cos²θ+（1+cotθ)sin²θ 已知cotθ=1/2,求sin²θ-2sinθcosθ+3cos²θ＝? 化简sin(θ-5π)•cot(π2-θ)•cos(8π-θ)tan(3π-θ)•tan(θ-32π)•sin(-θ-4 已知tan（π-α）=2,求sin²α-2sinαcosα-cos²α/4cos²α-3s [cot（θ+4π）·cos（θ+π）·sin^2（θ+3π）]/[tan（π+θ）·cos^3（-π-θ）] 1.化简sin²α+cosαcos(π/3+α)-sin²(π/6-α) sin(θ -5π)/tan(3π-θ)*cot(π/2-θ)/tan(θ -3/2π)*cos(8π-θ)/sin(- 化简：sin²α/(1+cotα) + cos²/(1+tanα) +sinαcosα 已知6sin²α+5sinαcosα-4cos²α=0,α∈(3π/2,2π),求tanα的值 化简:cos^2θcotθ+sin^2θtanθ+2cosθsinθ 已知tan（π/4+θ）+tan（π/4-θ)=4,且-π＜θ＜-π/2,求sin²θ-2sinθcosθ-c