简算41又1/3x3/4+51又3/4x4/5+61又1/5x5/6
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/13 01:34:37
简算41又1/3x3/4+51又3/4x4/5+61又1/5x5/6
应该是51又1/4吧
41又1/3x3/4+51又1/4x4/5+61又1/5x5/6
=(40+4/3)x3/4+(50+5/4)x4/5+(60+6/5)x5/6
=40x3/4+4/3x3/4+50x4/5+5/4x4/5+60x5/6+6/5x5/6
=30+1+40+1+50+1
=123
如果是51又3/4的话
41又1/3x3/4+51又3/4x4/5+61又1/5x5/6
=(40+4/3)x3/4+(50+7/4)x4/5+(60+6/5)x5/6
=40x3/4+4/3x3/4+50x4/5+7/4x4/5+60x5/6+6/5x5/6
=30+1+40+7/5+50+1
=122+7/5
=123又2/5
41又1/3x3/4+51又1/4x4/5+61又1/5x5/6
=(40+4/3)x3/4+(50+5/4)x4/5+(60+6/5)x5/6
=40x3/4+4/3x3/4+50x4/5+5/4x4/5+60x5/6+6/5x5/6
=30+1+40+1+50+1
=123
如果是51又3/4的话
41又1/3x3/4+51又3/4x4/5+61又1/5x5/6
=(40+4/3)x3/4+(50+7/4)x4/5+(60+6/5)x5/6
=40x3/4+4/3x3/4+50x4/5+7/4x4/5+60x5/6+6/5x5/6
=30+1+40+7/5+50+1
=122+7/5
=123又2/5
简算41又1/3x3/4+51又3/4x4/5+61又1/5x5/6
41又1/3x4/3+51又1/4x4/5+61又1/5x5/6=多少
31又1/2x2/3+41又1/3x3/4+51又1/4×4/5+61又1/5x5/6+71又1/6x6/7
1x1-2x2+3x3-4x4+5x5-6x6.-100x100+101x101
求解一个方程急 X(1次方)+X2+X3=5 X2+X3+X4=1 X3+X4+X5=-5 X4+X5+X1=-3 X5
解方程组X2+X3+X4=1 X1+X2+X3=5 X3+X4+X5=-5 X4+X5+X1=-3 X5+X1+X2=2
解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2
已知数据X1,X2,X3,X4,X5的平均数是X拔,则一组新数据X1+1,X2+2,X3+3,X4+4,X5+5的平均数
1x1 2x2 3x3 4x4 5x5```````nxn有什么规律
1x1 2x2 格式正确 3x3 4x4 5x5
求齐次线性方程组x1+2x2+x3+x4+x5=1 2x1+4x2+3x3+x4+x5=2 -x1-2x2+x3+3x4
1x2/1+2x3/1+3x4/1+4x5/1+5x6/1+6x7/1