根号下{[log2 （5)]^2-4log2(5)+4}+log2(1/5)

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/18 16:00:47

$根号下{[log2 （5)]^2-4log2(5)+4}+log2(1/5)$

令a=log2(5)
则log2(1/5)=-log2(5)=-a
且5>2²,所以a>2
a-2>0
原式=√(a²-4a+4)-a
=√(a-2)²-a
=|a-2|-a
=a-2-a
=-2

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