∫(COS2X)/(1十SinXCOSX)dX=
∫(COS2X)/(1十SinXCOSX)dX=
∫cos2x/(1+sinxcosx) dx 求详解.
1.∫(sinxcosx)/(1+sin^2x)dx
已知函数∫(x)=2√3sinxcosx+2cos2x-1(x∈R)
(2013•东莞二模)已知函数f(x)=23sinxcosx−2cos2x+1.
(2011•淮南一模)已知函数f(x)=cos2x−sin2x+23sinxcosx+1.
(2013•房山区一模)已知函数f(x)=2cos2x+23sinxcosx−1.
∫(cos2x/cos方x*sin方x)dx
凑微分法求定积分∫(上限 派/2,下限0)sinxcosx/(1+cosx^2)dx
求定积分∫1/sinxcosx dx(上限π/3,下限π/4),也如图,
∫sinxcosx/(1+sin^4x)dx
∫(X十SinX)/(1十COSX)dX=