2x+3y/2+3x+2y/5=11/3,3(2x+3y）/2=6（3x+2y）/7+2.5,求教啊= =

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2x+3y/2+3x+2y/5=11/3,3(2x+3y）/2=6（3x+2y）/7+2.5,求教啊= =
2x+3y/2+3x+2y/5=11/3 ,3(2x+3y）/2=6（3x+2y）/7+2.5

题目中第一式是不是应该是：(2x+3y)/2+(3x+2y)/5=11/3 , 否则这样出没意义.
如果是这样的话,解法如下：
15(2x+3y)+6(3x+2y)=110, 21(2x+3y)-12(3x+2y)=35
48x+57y=110,6x+39y=35
加减法解得：x=3/2, y=2/3
再问：好吧，我知道等于48x+57y=110,6x+39y=35。然后下面的我就算不出来，算了好几次= =
再答： 1) 48x+57y=110, 2)48x+312y=280, 2)-1)得255y=170，所以y=2/3，代入6x+39y=35就可以解得x=3/2

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5 若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2= 已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y 先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y 2x+3y/2+3x+2y/5=11/3,3(2x+3y）/2=6（3x+2y）/7+2.5,求教啊= = x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1