y=sin3(x-π 6) 1的对称轴
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|a-c|^2-3=a^2-2ac+c^2-3=1-2(cos3/2x-sin3/2x)+2-3=2(sin3/2x-cos3/2x)|b+c|^2-3=b^2+2bc+c^2-3=1+2(cosx/
令sinx=a,即y=a^3,求导y=3sin^2xcosx
向量a*向量b=cos3/2x*cosx/2+sin3/2x*(-sinx/2)=cos(3/2x+x/2)=cos2x向量a+向量b=(cos3/2x,sin3/2x)+(cosx/2,-sinx/
∵函数y=sin3(3x+π4),∴y′=3sin2(3x+π4)cos(3x+π4)×3=9sin2(3x+π4)cos(3x+π4),故选B.
对x的偏导数是6x+1--->f(x,y)=3x^2+x+C(y)f(x,2x)=x^2+3x----->3x^2+x+C(2x)=x^2+3x------>C(2x)=-2x^2+2x------>
y=sin³(3X+2)y'=[3sin²(3x+2)]*cos(3x+2)*3=9sin²(3x+2)cos(3x+2)看复合了几次
y=sin(2/3x)+(√3/2)cos(2/3x)-(1/2)sin(2/3x)=(1/2)sin(2/3x)+(√3/2)cos(2/3x)=sin(2/3x+π/3).两相邻对称轴之间的距离就
y=sin(x+y).两边对x求导得:y’=cos(x+y)(1+y')y'=cos(x+y)/(1-cos(x+y))所以:dy=[cos(x+y)/(1-cos(x+y))]dx再问:y'=cos
向量a=(cos(3x/2),sin(3x/2)),b=(cos(x/2),sin(x/2)),所以a·b=cos(3x/2)cos(x/2)+sin(3x/2)sin(x/2)=cos(3x/2–x
亲有木有打错题目啊是a+b的模吧?再问:是a+b的模,打错了,不好意思,麻烦解答一下吧,谢谢再答:(1)a·b(等于a的坐标乘b的坐标相加。)=cos3/2x·cosx/2-sin3/2x·sinx/
adotb=(cos(3x/2),sin(3x/2))dot(cos(x/2),-sin(x/2))=cos(3x/2+x/2)=cos(2x)a+b=(cos(3x/2),sin(3x/2))+(c
1、|a+b|^2=(cos3/2x-sinx/2)^2+(sin3/2x-cosx/2)^2=3(cos3/2x)^2-2*cos3/2x*sinx/2+(sinx/2)^2+(sin3/2x)^2
y=2^arccot(x)-sin3y'=2^arccotx*[-1/(1+x²)]*ln2dy=2^arccotx*[-1/(1+x²)]*ln2dx
f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)=cos2xcosπ/3+sin2xsinπ/3+2sin(x+π/4)cos(x+π/4)=1/2cos2x+根3/2si
y=sin3/4x设周期为t则sin2/3x=sin3/4(x+t)=sin(3/4x+3/4t)因为sin周期是2Pi所以3/4t=2Pi(这个应该理解吧?)所以t=8/3*Pi下面两题是类似的,自
①a·b=cos(3/2x)*cos(x/2)-sin(3/2x)*sin(x/2)=cos(3/2x+x/2);a+b=(cos3/2x+cosx/2,sin3/2x-sinx/2);使用和差化积公
全微分吗?z=arctan(y/x)∂z/∂x=1/(1+y²/x²)*y=x²y/(x²+y²)∂z/ͦ
这个看看你的课本中关于诱导公式这一节你就会解了嘿嘿符号太难打了