x.y满足x 3³ 4³ y 3³ 6³=1
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x=log2(y)则X1+2X2+3X3=log2(y1)+2log2(y2)+3log2(y3)=log2(y1)+log2(y2^2)+log2(y3^3)=log2(y1y2^2y3^3)=1所
∵2x+y=0,∴4x3+2xy(x+y)+y3=2x[2x2+y(x+y)]+y3=2x[x(2x+y)+y2]+y3=2xy2+y3=y2(2x+y)=0.故答案为:0.
很高兴喂你解答!原式=4√[(x^2+xy+y^2)/(x-y)*1/2√[(x^2-xy+y^2)/(x+y)*3√(x^3+y^3)=6√[(x^2+xy+y^2)/(x-y)*√[(x^2-xy
∵代数式x3+y3+3x2y+axy2含有因式x-y,∴当x=y时,x3+y3+3x2y+axy2=0,∴令x=y,即x3+x3+3x3+ax3=0,则有5+a=0,解得a=-5.将a=-5代入x3+
(x+y+z)^3-x^3-y^3-z^3=3yx^2+3xy^2+3xz^2+3yz^2+3zx^2+3zy^2+6xyz=3xy(x+y)+3z^2(x+y)+3z(x^2+y^2+2xy)=3x
如果你的X2是x的平方,X3是x的三次方那么答案是:-(x-y+z)*(x-y-z)*(x+y-z)
A+B+C=(x3+3x2y-5xy2+6y3-1)+(y3+2xy2+x2y-2x3+2)+(x3-4x2y+3xy2-7y3+1)=(1+1-2)x3+(3+1-4)x2y+(-5+2+3)xy2
(x+y)³=x³+y³+3x²y+3xy².记忆方法:各立方,然后3x方y,3xy方(x+y)³=x³-y³-3x
原方程可化为x(x+1)(x+2)+3(x2+x)=y(y-1)(y+1)+2,∵三个连续整数的乘积是3的倍数,∴上式左边是3的倍数,而右边除以3余2,这是不可能的.∴原方程无整数解.故选A.
^3代表3次方,^2代表平方X^3+X^2-Y^3-Y^2=(x^3-y^3)+(x^2-y^2)=(x-y)(x^2+xy+y^2)+(x-y)(x+y)=(x-y)(x^2+xy+y^2+x+y)
f(x,y)=In(1+x2+y2)+1-x3/15-y3/4?应该是f(x,y)=In(1+x²+y²)+1-x³/15-y³/4吧?楼主的问题没法解答.楼主是要
求偏导另其等于0即可
x3(y-z)+y3(z-x)+z3(x-y)=x3(y-z)+y3(z-x)-z3(y-z)-z3(z-x)=(x3-z3)(y-z)+(y3-z3)(z-x)=(x-z)(y-z)(x2+xz+z
设x1+y1=x2+y2=x3+y3=x4+y4=X5+y5=A,y1=A-x1,y2=A-x2,...,y5=A-x5.yˉ=(y1+y2+...+y5)/5=(A-x1+A-x2+...+A-x5
x+y=1(x+y)^2=x^2+2xy+y^2=1(x+y)^3=x^3+y^3+3xy(x+y)=1而x^3+y^3=1/3,代入得:3xy=2/3xy=2/9由于x=1-y;故代入xy=2/9;
A-B=(x3+2y3-xy2)-(﹣y3+x3+2xy2)=x³+2y³-xy²+y³-x³-2xy²=3y³-3xy²
x^3+y^3+z^3+(x+y)^3+(y+z)^3+(z+x)^3=[x^3+(y+z)^3]+[y^3+(z+x)^3]+[z^3+(x+y)^3]=(x+y+z)(x^2-xy+y^2-xz+
x3+3xy-y3=(x-y)(x^2+y^2+xy)+3xy=-x^2-y^2+2xy=-(x-y)^2=-1