sin^2x*sin^2(120x)sin^2(120-x)

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sin^2x*sin^2(120x)sin^2(120-x)
求函数f(x)=(sin⁴x+cos⁴x+sin²xcos²x)/(2-si

f(x)={[(sinx)^2+(cosx)^2]^2-(sinxcosx)^2}/(2-sin2x)=[1-(sinxcosx)^2]/(2-2sinxcosx)=(1+sinxcosx)(1-sinxcosx)/[2(1-sinxcos

Sqrt[2] * { Sin( x + π/4 ) * cos[ π/4 ] + Cos[ x + π/4] * si

Sin(x+π/4)*cos[π/4]+Cos[x+π/4]*sin[π/4]=sin[(x+π/4)+π/4]=sin(x+π/2)正弦函数的和角公式再问:正弦函数的和角公式..我们还没学到..你qq多少再答:sin(a+b)=sinac

在mathematica里输入Plot[Sin[x] Sin[x + 2] - Sin[x + 1]Sin[x + 1]

楼上都错了,图像没问题这个表达式实际是个常数,你可以运行TrigReduce[Sin[x]Sin[x+2]-Sin[x+1]^2]看看,结果为1/2(-1+Cos[2])只不过Plot的自动选择坐标系使得图像刚好与横坐标重合了.你可以运行P

y=sin^2x-3sinxcosx+4cos^2x是否等于y=sin^2x+cos^2x+3cos^2x-3/2*si

如果说化简应该不对结果应该是常数+sinT或者cosT你的结果还能继续化下去

化简 cos^2(x)*sin^2(x)-sin^2(x)

=sin^2(x)*[cos^2(x)-1]=-sin^4(x)再答:别忘了负号再问:嗯谢谢

x*(1+sin^2 x )/sin^2x 不定积分

原式=∫x*(csc^2x+1)=∫x*csc^2x+x(分开积分)前面=-x*cotx+∫cotx=-x*cotx+ln|sinx|后面=1/2x^2记得加C

已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x

sinx=2cosx,sin^2x=4cos^2xsin^2x=4-4sin^2x,sin^2x=4/5(cosx+sinx)/(cosx-sinx)+sin^2x=(1+tanx)/(1-tanx)+sin^2x=-3+4/5=-11/5

(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x

sin^4x-sin^2xcos^2x+cos^4x=sin^4x+2sin^2xcos^2x+cos^4x-3sin^2xcos^2x=(sin^2x+cos^2x)^2-3sin^2xcos^2x=1-3sin^2xcos^2x所以分子

化简(sin^2 x/sin x-cosx)-(sin x+cosx/tan^2 x-1)

tan²-1=sin²x/cos²x-1=(sin²x-cos²x)/cos²x=(sinx+cosx)(sinx-cosx)/cos²x所以(sinx+cosx)/(t

为什么|sin(2x+pi)|=|sin(2x)|呢?

sin在(0,PI)是中心对称的.意思是SIN(X+PI)=-SIN(X)加绝对值就相等了.

解方程 sin 2x + sin x = 0

sin2x+sinx=02sinxcosx+sinx=0sinx(2cosx+1)=0①党sinx=0x=kπ②党(2cosx+1)=0cosx=-1/2x=kπ/2+π/3

化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x

sin^4x-sin^2xcos^2x+cos^4x=sin^4x+2sin^2xcos^2x+cos^4x-3sin^2xcos^2x=(sin^2x+cos^2x)^2-3sin^2xcos^2x=1-3sin^2xcos^2x所以分子

证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+

sinx+siny+sinz-sin(x+y+z)=4sin[(x+y)/2]sin[(x+z)/2]sin[(y+z)/2]sinx+siny+sinz-sin(x+y+z)=2sin[(x+y)/2]cos[(x-y)/2]+sinz-

泰勒公式的为什么㏑( 1 + sin X ) = sin X - ( sin X )²/2 +(sin X )

你好,第一:首先将㏑(1+X)用麦克劳林公式(泰勒公式的推广)分解开就是X-(X)²/2+(X)³/3-(X)∧4+o(∧4X),第二:将㏑(1+X)中的X换为sinX就ok了,很简单,希望你能理解

高一三角函数化简 sin^2(x-30)+sin^2(x+30)-sin^2(x)

sin^2(x-30)+sin^2(x+30)-sin^2(x)=(1-cos(2x-60))/2+(1-cos(2x+60))/2-sin^2x=1-1/2[cos(2x-60)+cos(2x+60)]-sin^2x=-1/2[cos2x

matlab画y=sin(x)+sin(2*x)+...+sin(20*x)的图像

x=0:0.01:1;y=0;fori=1:20y=y+sin(i*x);endplot(y);