设x y=5,xy=-3

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设x y=5,xy=-3
先化简,再求值 ⒈2(Xy+Xy)-3(Xy-xy)-4Xy,其中X=1,y=-1

1.2(Xy+Xy)-3(Xy-xy)-4Xy=2*2xy-0-4xy=4xy-4xy=02.1/2ab-5aC-(3acb)+(3aC-4aC)=1/2ab-5ac-3acb-ac=1/2ab-6a

已知xy^2=-2,求-xy(x^2y^5-xy^3-y)的值.

-xy(x^2y^5-xy^3-y)=-(xy^2)^3+(xy^2)^2+xy^2=-(-2)^3+4-2=8+4-2=10

设xy>0,且xy=4x+y+12,求xy的最小值

xy-12=4x+y≥2√(4xy)=4√(xy)xy-4√(xy)-12≥0(√(xy)-6)(√(xy)+2)≥0√(xy)≤-2,√(xy)≥6因为√(xy)≥0所以√(xy)≥6xy≥36所以

设x+y=5,xy=负3,求代数式(2x减3y减2xy)减(x减4y+xy)的值

x+y=5xy=-3(2x-3y-2xy)-(x-4y+xy)=2x-3y-2xy-x+4y-xy=x+y-3xy=5-3×(-3)=5+9=14

设x+y=5,xy=3,求代数式(2x-3y-2xy)-(x-4y+xy)的值.

原式=2x-3y-2xy-x+4y-xy=x+y-3xy=5-3*3=5-9=-4

xy'=y+xy的

xdy=(y+xy)dxdy/y=((1+x)/x)dxln|y|=ln|x|+x+cy=±e^(ln|x|+x+c)其中c是常数再问:真还不理解我们是选择题:y=cxe^xy=c+x-x^2y=cs

已知(x+1)²+|y-1|=0,求2(xy-5xy²)-(3xy²-xy)得值

解(x+1)平方+/y-1/=0∴x+1=0,y-1=0∴x=-1,y=1∴2(xy-5xy平方)-(3xy平方-xy)=(2xy+xy)+(-10xy平方-3xy平方)=3xy-13xy平方=3×(

设A=2x²-3XY+Y²,B=4X²-6XY-3Y²,且(X-5)和(Y+2)

(X-5)和(Y+2)²是互为相反数则|x-5|+(Y+2)²0则x-5=0,Y+2=0则x=5,Y=-23A-2B=3(2x²-3XY+Y²)-2(4X

设x+y=5,xy=负3,求(2x-3y-2xy)-(x-4y+xy)的值

(2x-3y-2xy)-(x-4y+xy)=2x-3y-2xy-x+4y-xy=(2-1)x+(-3+4)y+(-2-1)xy=x+y-3xy因为x+y=5,xy=-3所以原式=5+9=14

化简:xy分之3x^2+2xy-xy分之2x^2-xy=

(3x^2+2xy)/xy-(2x^2-xy)/xy=(3x^2+2xy-2x^2+xy)/xy=(x^2+3xy)/xy=x(x+3y)/xy=(x+3y)/y

设x的平方+xy=3,xy+y的平方=—2,求2x的平方—xy—3y的平方的值

x²+xy=3xy+y²=-22x²-xy-3y²=2(x²+xy)-3(xy+y²)=6+6=12

设S={1,2,3,4},定义 S上的二元运算如下:xy=(xy)(mod 5),( ∀ x,y ∈ S)

a=array(1,2,3,4,5)这句后a[0]=1;a[1]=2;.a[4]=5;//注,没有a[5]了哦s=s+a(k),就是把s+a(k)后的值,再赋给s

已知x+y=3 xy=-5 求x设abc=1 求x²+3xy+2y²/x²y+2xy

分数可以打清楚点吗?不然不知道到底哪几项在分子上再问:/前面都是分子再答:图片传不上来,我在贴吧发给你行不行?再问:行~~

设e^xy-xy^2=Siny,求dy/dx

你好!两边对x求导:e^(xy)*(y+xy')-y^2=y'cosy解得y'=(y^2-ye^(xy))/(xe^(xy)-cosy)

设x、y为实数,且x2+xy+y2=3,求x2-xy+y2的最大值和最小值.

设x2-xy+y2=M①,x2+xy+y2=3②,由①、②可得:xy=3−M2,x+y=±9−M2,所以x、y是方程t2±9−M2t+3−M2=0的两个实数根,因此△≥0,且9−M2≥0,即(±9−M

设A=2x²-3xy.

|x-2a|+(y+3)²=0所以x-2a=0,y+3=0x=2a,y=-3B-2A=(4x²-6xy+2y²-3x-y)-2(2x²-3xy+y²-

X+y=3 xy=-5 Xy=?

X+y=3xy=-5X-y=?(x-y)^2=(X+y)^2-4xy=9+20=29则x-y=±根号29

已知x^-xy=5,xy-y^=-3,求式子3(x^-xy)-xy+y^的值

3(x^2-xy)-xy+y^2=3(x^2-xy)-(xy-y^2)=3*5-(-3)=15+3=18

已知xy^2=-2 求-xy(x^2y^5-xy^3-y)

原式=-xy²(x²y^4-xy²-1)∵xy²=-2原式=2((-2)²-(-2)-1)=10