a b=x y=2,ax by=5,问

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a b=x y=2,ax by=5,问
已知直线y=2x+b与曲线xy=2相交于AB两点,且AB=5,求实数b的值

设A点坐标(Xa,Ya)B点坐标(Xb,Yb)(Xa-Xb)平方+(Ya-Yb)的平方=25y=2x+bxy=2(2x+b)x=22x平方+bx-2=0Xa+Xb=-b/2Xa*Xb=-1(Xa-Xb

小娜和小洋同时解一个关于x,y的二元一次方程组{axby=16① bx+ay=1②小娜把方程①抄错了,求得的解为

x=-1,y=3代入②得:-b+3a=1x=3,y=2代入①得:6ab=16解得:(怀疑题目有问题,因为a、b为无理数)求出a、b之后,再代入,求原来的解.

先化简,再求值 ⒈2(Xy+Xy)-3(Xy-xy)-4Xy,其中X=1,y=-1

1.2(Xy+Xy)-3(Xy-xy)-4Xy=2*2xy-0-4xy=4xy-4xy=02.1/2ab-5aC-(3acb)+(3aC-4aC)=1/2ab-5ac-3acb-ac=1/2ab-6a

已知xy^2=-2,求-xy(x^2y^5-xy^3-y)的值.

-xy(x^2y^5-xy^3-y)=-(xy^2)^3+(xy^2)^2+xy^2=-(-2)^3+4-2=8+4-2=10

xy'=y+xy的

xdy=(y+xy)dxdy/y=((1+x)/x)dxln|y|=ln|x|+x+cy=±e^(ln|x|+x+c)其中c是常数再问:真还不理解我们是选择题:y=cxe^xy=c+x-x^2y=cs

已知(x+1)²+|y-1|=0,求2(xy-5xy²)-(3xy²-xy)得值

解(x+1)平方+/y-1/=0∴x+1=0,y-1=0∴x=-1,y=1∴2(xy-5xy平方)-(3xy平方-xy)=(2xy+xy)+(-10xy平方-3xy平方)=3xy-13xy平方=3×(

当x=3,y=3分之1时,求代数出3xy-[2xy-2(xy-2分之3xy)+xy]+3xy的值

3xy-[2xy-2(xy-2分之3xy)+xy]+3xy=6xy-[2xy-2xy+3xy+xy)=6xy-4xy=2xy=2×3×3分之1=2

(8xy-3x平方)-5xy-2(3xy-2x平方),其中,x=2,y=-1

(8xy-3x平方)-5xy-2(3xy-2x平方)=8xy-3x²-5xy-6xy+4x²=x²-3xy=4+6=10

已知x+y分之xy=2,那么3x-5xy+3y分之3xy-x-y=

xy/(x+y)=2∴xy=2(x+y)(3xy-x-y)/(3x-5xy+3y)=[6(x+y)-x-y]/[3x+3y-10(x+y)]=5(x+y)/[-7(x+y)]=-5/7

若x-y=5,xy=6,求x^2-xy^2和x^2y+xy^2

x=-1,y=-6或x=6,y=1代入式子得x^2-xy^2=37或30x^2y+xy^2=-42或42

合并同类项计算:-a-a=()-3xy+3xy=()-3m²+10m²=()-5ab+2ab-ab=

:-a-a=(-2a)-3xy+3xy=(0)-3m²+10m²=(7m²)-5ab+2ab-ab=(-4ab)2y+3xy-5y=(3xy-3y)3a+2b-3b+5a

已知x2+xy=2,y2+xy=5,则12x2+xy+12y2=___.

∵x2+xy=2,y2+xy=5,∴x2+2xy+y2=7,则原式=12(x2+2xy+y2)=72,故答案为:72

化简:xy分之3x^2+2xy-xy分之2x^2-xy=

(3x^2+2xy)/xy-(2x^2-xy)/xy=(3x^2+2xy-2x^2+xy)/xy=(x^2+3xy)/xy=x(x+3y)/xy=(x+3y)/y

已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y=

因为xy/(x+y)=1/2所以x+y=2xy原式=3(x+y)-5xy/(-x-y+3xy)=3*2xy-5xy/(-2xy+3xy)=xy/xy=1

已知x2-xy=3,xy-y2=-5,试求代数式x2+2xy-3y2的值.

x2+2xy-3y2=x2-xy+3xy-3y2=x2-xy+3(xy-y2),∵x2-xy=3,xy-y2=-5,∴x2+2xy-3y2=3+3×(-5)=-12.

若关于x,y的方程组4x+y=5,axby=3和3x-2y=1,ax-by=1有相同的解,求a,b的值

解方程组4x+y=53x-2y=1得,x=1,y=1代入另外两个方程a+b=3(这个方程应该是ax+by=3吧)a-b=1解得z=2,b=1

若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值

x+y=5xy(2x-3xy+2y)/(x+2xy+y)=[2(x+y)-3xy]/[(x+y)+2xy]=(2×5xy-3xy)/(5xy+2xy)=7xy/7xy=1再问:若x+1/x=3,求(x

已知xy^2=-2 求-xy(x^2y^5-xy^3-y)

原式=-xy²(x²y^4-xy²-1)∵xy²=-2原式=2((-2)²-(-2)-1)=10